Mov ax offset array

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August undefined, 2024

Nettetmov ax, offset ASC_TBL + 5 is legal, and shorter (3 bytes for mov ax, imm16 vs. 4 bytes for LEA: opcode + modrm + disp16). Either way the absolute address is calculated by … Nettetmov ax, BYTE PTR A[0] or to: mov ax, A[BYTE PTR 0] And even changing ax or al with all these combinations is failing.. or trying to acces the OFFSET of array A: mov al, A[OFFSET A] I don't know where's the problem.. Thank you for helping!

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Nettetmov bx, data实际上应该理解为： mov bx, [data] 也即,将内存中data处的16位数据赋给bx这个寄存器。而mov bx, offset data则是将data这个内存单元的偏移地址赋值给bx … Nettet14. okt. 2024 · MOV AX, [SI] [BX] ; move a value from two memory location starting [SI+BX] to register AX MOV AL, array ; move an 8-bit value from the offset of the array in AL register LEA: This instruction is used to load the effective address in the register specified in the instruction. The general format and usage of this instruction is given … psycho sid wrestling

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Nettetmov esi,OFFSET arrayW mov ax,[esi] moves 10h to ax mov ax,[esi + 2] moves 20h to ax mov ax,[esi + 4] moves 30h to ax Example 4: Index Scaling Factor You can scale an … Nettet31. des. 2024 · I searched this question on The Internet and solving is MOV AX, [BX]. In RAM memory, you can only store numbers. To store the letter "A", the number 65 is … Nettet19. jun. 2024 · 指令格式： MOV AX, COUNT [SI] 或 MOV AX, [COUNT+SI] 假设 (DS)=3000H, (SI)=2000H, COUNT=3000H, 则: PA = 35000H 假设 (35000H)=1234H, 那么 (AX)=1234H * 适于数组、字符串、表格的处理 1.6基址变址寻址方式* 指令格式： MOV AX, [BX] [DI] MOV AX, [BX+DI] MOV AX, ES: [BX] [SI] * 适于数组、字符串、表格的处理 * … hospital st. andreas großengottern

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Mov ax offset array

NettetWhen one double word is moved to EAX, it overwrites the existing value of AX. Example .data OneByte BYTE 78h oneWord WORD 1234h oneDword DWORD 12345678h .code mov eax, 0 ; EAX = 00000000h mov al, OneByte ; EAX = 00000078h mov ax, oneWord ; EAX = 00001234h mov eax, oneDword ; EAX = 12345678h mov ax,0 ; EAX = 12340000h Nettet32: mov DX,BX ; DX keeps the actual array size 33: sub DX,OFFSET array ; DX := array size in bytes 34: shr DX,1 ; divide by 2 to get array size

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Nettetmov ax,array[bx][di] ; move bytes 3 and 4 into AX, byte 3 into ;AL, byte 4 into AH . EE-314 Summer 2003 ... stc mov cx,count mov si,offset array label1: adc ax,word ptr [si] add si,2 loop label1 label2: Question A: The body of the loop will execute 4 times (CX = 4). On each pass through the loop, AX will have the following values: NettetMOV AX, [SI+BX+20] Or MOV AX, [SI] [BX]+20 In this case, the physical address will be DS (Shifted left) + SI + BX + 20. Now, if we replace BX with BP then the physical address is equal to SS (Shifted left) + SI + BX + 20. Now, let us have a look on these two instructions: MOV AX, [BX] [BP]+20 MOV AX, [SI] [DI]+20

NettetQuestion: Which number gets moved into AX? Also, what is the final result located in the AX register after completing execution of the following code?: (You must answer both parts of the question for full credit) .data array WORD 9, 17, 33, 65 .code mov esi, offset array add esi, 4 mov ax, [esi] neg ax Assembly x86 NettetThe LOOP instruction creates a counting loop Syntax: LOOP target Logic: ECX ECX – 1 if ECX != 0, jump to target Implementation: The assembler calculates the distance, in …

NettetMOV AX, [ BX ] = MOV AX, DS:[BX] Value in BX is used as address offset to a memory operand []CPU loadsAX with contents of ÖAX:= m[DS:BX] CPU loads AX with contents of contents of that memory Indirect addressing mode use registers as a pointer, hi h i i t t h dl ! (l t ) SYSC3006 9 which is a convenient way to handle an array! (later) Nettet23. feb. 2024 · 你可以使用如下汇编语言编写冒泡排序程序： mov ax, [array] ; 将数组首地址存入ax mov cx, [arraysize] ; 将数组大小存入cx mov bx, 0 ; 将比较次数存入bx l1: cmp [ax + bx], [ax + bx + 1] ; 比较数组中的两个元素 jl l2 ; 如果第一个元素小于第二个元素，则跳到l2 mov dx, [ax + bx] ; 将第 ...

Nettet23. jun. 2024 · 1 Answer. Sorted by: 3. You are confused by the braindead abomination that is AT&T syntax. In Intel's intended syntax mov 0x8 (%rsp), %rsi translates to: mov …

Nettet23. feb. 2024 · MOV AX, 2000 MOV CS, AX Displacement or direct mode – In this type of addressing mode the effective address is directly given in the instruction as displacement. Example: MOV AX, [DISP] MOV AX, [0500] Register indirect mode – In this addressing mode the effective address is in SI, DI or BX. hospital st pete beach flNettetmov esi, OFFSET array call proc_1 add eax, 5 add esi, TYPE array mov [esi], ax INVOKE ExitProcess,0 main ENDP proc_1 PROC add esi, TYPE array add ax, 10 mov [esi], ax ret proc_1 ENDP END MAIN ; Please explain how the data (array_type TYPE ?) works and tell me the answer. Thank you in advance Expert Answer 1st step All steps … psycho sideshow demon freaksNettet23. des. 2024 · 指令MOV AX，VAR [BX]属于寄存器相对寻址。 1 [BX,SI,DI,BP] 2 3 [BX+SI]... 4 5 idea [BX]... 6 7 [BX] [BP].... 8 9 [BX].idea... 10 11 [BX].idea [SI] View Code 三、简答题（每题2 分，共6 分） 1. 下列语句在存储器中分别为变量数据区分配多少个字节单元？（1）VAR1 DD 10 ==> 双字 4bytes （2）VAR2 DW 4 DUP (?)，2 ==> 10bytes … psycho singer maxhttp://www.math.uaa.alaska.edu/~afkjm/cs221/handouts/irvine4.pdf hospital st thomas viNettet9. apr. 2024 · The difference should be obvious, the first one only loads al (the low 8 bits) while the second loads ax (16 bits). Note that al is zero in both cases as expected. The 3(%rbx) and the arr+3 do the same the important thing is the movb vs the movw. hospital st thomas usvi hospital staff education programNettetQ20. Two arrays of unsigned 8 -bit data numbers are stored from location arr1 and arr2.Write a program that will add the contents of arr1 with arr2 and store the addition result including the carry in an unsigned 16-bit array arr3.The count of data in arr1 and arr2 is 5. For e.g. if the data in arr1 is 45h, 82h, 91h, 73h, 13h hospital st stephen nb